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Straight-Line Motion: Position, Velocity, Acceleration

AP Calculus AB· difficulty 3/5

For v(t)=t2−4v(t) = t^2 - 4, the <strong>speed</strong> at t=1t = 1 is

  • A

    33

    check_circle
  • B

    00

  • C

    55

  • D

    −3-3

Explanation

Speed = ∣v(t)∣|v(t)|. v(1)=−3v(1) = -3, speed =3= 3.

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