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Straight-Line Motion: Position, Velocity, Acceleration

AP Calculus AB· difficulty 2/5

A particle has position s(t)=t3−3t2+4s(t) = t^3 - 3t^2 + 4 (m, s). Its velocity at t=2t = 2 is

  • A

    12 m/s12~\text{m/s}

  • B

    3 m/s3~\text{m/s}

  • C

    0 m/s0~\text{m/s}

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  • D

    6 m/s6~\text{m/s}

Explanation

v(t)=s′(t)=3t2−6tv(t) = s'(t) = 3t^2 - 6t. v(2)=12−12=0v(2) = 12 - 12 = 0.

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