Using Accumulation Functions and Definite Integrals

AP Calculus AB· difficulty 3/5

Water flows in at rate f(t)=100f(t) = 100 L/h and flows out at rate g(t)=30+5tg(t) = 30 + 5 t L/h on [0,4][0, 4]. Net change in tank:

  • A

    160160

  • B

    240240

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  • C

    280280

  • D

    320320

Explanation

Net rate =705t= 70 - 5t. 04(705t)dt=28040=240\int_0^4 (70 - 5t)\,dt = 280 - 40 = 240.

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