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Position, Velocity, and Acceleration using Integrals

AP Calculus AB· difficulty 2/5

A particle starts at s(0)=5s(0) = 5 with velocity v(t)=3tv(t) = 3t. Position at t=4t = 4:

  • A

    2424

  • B

    2929

    check_circle
  • C

    4848

  • D

    1212

Explanation

s(t)=5+∫0t3u du=5+3t2/2s(t) = 5 + \int_0^t 3u\,du = 5 + 3t^2/2. s(4)=5+24=29s(4) = 5 + 24 = 29.

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