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Average Value of a Function on an Interval

AP Calculus AB· difficulty 2/5

Average of sin⁡x\sin x on [0,π][0, \pi] is

  • A

    00

  • B

    2π\tfrac{2}{\pi}

    check_circle
  • C

    11

  • D

    1π\tfrac{1}{\pi}

Explanation

1π∫0πsin⁡x dx=(1/π)(2)=2/π\dfrac{1}{\pi}\int_0^\pi \sin x\,dx = (1/\pi)(2) = 2/\pi.

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