Chromosomal Inheritance

AP Biology· difficulty 3/5

A test cross of AaBb x aabb produced 1000 offspring. Expected ratio under independent assortment is 1:1:1:1 (250 each). Observed: 420, 80, 75, 425.

Phenotype Count AB Ab aB ab

The skewed distribution is best explained by:

  • A

    Sampling error in a large population.

  • B

    Genetic linkage; AB and ab are parental gametes, Ab and aB are recombinants.

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  • C

    Independent assortment producing equal frequencies.

  • D

    Codominance of the alleles.

Explanation

Excess parental-type offspring (AB and ab) plus a small recombinant class (Ab, aB) indicates the loci are linked on the same chromosome. Map distance ~ (80+75)/1000 x 100 = 15.5 cM.

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