Hardy-Weinberg Equilibrium

AP Biology· difficulty 1/5

Allele Frequency A p = 0.7 a q = 0.3 Population at HW equilibrium

What proportion of the population is expected to be heterozygous (Aa)?

  • A

    0.42

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  • B

    0.09

  • C

    0.49

  • D

    0.21

Explanation

2pq = 2 x 0.7 x 0.3 = 0.42. Approximately 42% of the population is expected to be heterozygous.

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