In a randomly mating population at Hardy-Weinberg equilibrium, the dominant allele frequency p = 0.7 and the recessive allele frequency q = 0.3.
Assuming Hardy-Weinberg equilibrium, what fraction of the population is heterozygous?
- Acheck_circle
0.42
- B
0.09
- C
0.49
- D
0.30
Explanation
Heterozygote frequency = 2pq = 2(0.7)(0.3) = 0.42, illustrating that intermediate allele frequencies maximize heterozygosity.