Chromosomal Inheritance

AP Biology· difficulty 2/5

A heterozygous AaBb fruit fly is testcrossed to a homozygous recessive aabb partner. The phenotypic counts of 1000 progeny are listed.

Test cross of dihybrid AaBb x aabb Phenotype Count AaBb 410 aabb 390 Aabb 95 aaBb 105

What is the recombination frequency between the A and B loci?

  • A

    Approximately 20%, indicating linked genes about 20 mu apart

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  • B

    Cannot be calculated from the data

  • C

    Approximately 1%, indicating tight linkage

  • D

    Exactly 50%, indicating unlinked genes

Explanation

Recombinants = 95 + 105 = 200 of 1000 total = 20%. Recombination below 50% indicates linkage; the value (~20 mu) estimates map distance between A and B.

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