In a population in HWE with q = 0.1, what is the heterozygote frequency 2pq?
- A
0.10
- B
0.81
- Ccheck_circle
0.18
- D
0.99
Explanation
p = 0.9; 2pq = 2(0.9)(0.1) = 0.18.
Hardy-Weinberg Equilibrium
AP Biology· difficulty 3/5
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