Newton's Second Law in Rotational Form

AP Physics 1· difficulty 2/5

A flywheel (I=0.50 kg⋅m2I = 0.50~\text{kg·m}^2) is acted on by a net torque of 4.0 N⋅m4.0~\text{N·m}. Its angular acceleration is

  • A

    0.13 rad/s20.13~\text{rad/s}^2

  • B

    20 rad/s220~\text{rad/s}^2

  • C

    8.0 rad/s28.0~\text{rad/s}^2

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  • D

    2.0 rad/s22.0~\text{rad/s}^2

Explanation

α=τ/I=4.0/0.50=8.0 rad/s2\alpha = \tau/I = 4.0/0.50 = 8.0~\text{rad/s}^2.

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