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Newton's Second Law in Rotational Form

AP Physics 1· difficulty 2/5

A wheel (I=0.20 kg⋅m2I = 0.20~\text{kg·m}^2) experiences a constant net torque of 0.80 N⋅m0.80~\text{N·m}. After 5.0 s5.0~\text{s}, starting from rest, its angular speed is

  • A

    10 rad/s10~\text{rad/s}

  • B

    20 rad/s20~\text{rad/s}

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  • C

    2 rad/s2~\text{rad/s}

  • D

    4 rad/s4~\text{rad/s}

Explanation

α=0.80/0.20=4.0 rad/s2\alpha = 0.80/0.20 = 4.0~\text{rad/s}^2. ω=αt=20 rad/s\omega = \alpha t = 20~\text{rad/s}.

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