Rotational Equilibrium and Newton's First Law in Rotational Form

AP Physics 1· difficulty 2/5

A student applies a force at the rim of a wheel of radius 0.40 m0.40~\text{m} to produce 20 N⋅m20~\text{N·m} clockwise torque. A second force of 80 N80~\text{N} is applied tangentially at the rim counterclockwise. Is the wheel in rotational equilibrium?

  • A

    No — the counterclockwise torque wins.

    check_circle
  • B

    No — the clockwise torque wins.

  • C

    Cannot tell without the wheel's mass.

  • D

    Yes — both torques are equal.

Explanation

CCW torque: (0.40)(80)=32 N⋅m(0.40)(80) = 32~\text{N·m} > 20 N⋅m20~\text{N·m} CW. Net torque is counterclockwise, so not in equilibrium.

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