Rotational Kinetic Energy

AP Physics 1· difficulty 3/5

A bowling ball (I=25MR2I = \tfrac{2}{5}MR^2) rolls at 5 m/s5~\text{m/s} along a frictionless lane (no slipping). Its mass is 7 kg7~\text{kg}. Its <strong>total</strong> kinetic energy is

  • A

    122.5 J122.5~\text{J}

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  • B

    245 J245~\text{J}

  • C

    87.5 J87.5~\text{J}

  • D

    175 J175~\text{J}

Explanation

K=710Mv2=0.7(7)(25)=122.5 JK = \tfrac{7}{10}M v^2 = 0.7(7)(25) = 122.5~\text{J}.

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