Rolling

AP Physics 1· difficulty 3/5

A solid sphere rolls without slipping from rest down height hh. Its translational speed at the bottom is

  • A

    (4/3)gh\sqrt{(4/3)gh}

  • B

    2gh\sqrt{2gh}

  • C

    (10/7)gh\sqrt{(10/7)gh}

    check_circle
  • D

    gh\sqrt{gh}

Explanation

Total KE: 12Mv2(1+2/5)=710Mv2=Mghv=(10/7)gh\tfrac{1}{2}M v^2(1 + 2/5) = \tfrac{7}{10}M v^2 = M g h \Rightarrow v = \sqrt{(10/7)gh}.

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