AP Physics 1 · Topic 6.5

Rolling Practice

Part of Energy and Momentum of Rotating Systems.(TOP-6.E)

Practice questions

19

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Sample questions

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  1. Sample 1difficulty 1/5

    A hoop of radius 0.20 m0.20~\text{m} rolls without slipping at a translational speed of 3.0 m/s3.0~\text{m/s}. What is its angular speed?

    • A

      0.60 rad/s0.60~\text{rad/s}

    • B

      6.0 rad/s6.0~\text{rad/s}

    • C

      1.5 rad/s1.5~\text{rad/s}

    • D

      15 rad/s15~\text{rad/s}

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    Why

    Rolling constraint: v=Rωω=v/R=3.0/0.20=15 rad/sv = R\omega \Rightarrow \omega = v/R = 3.0/0.20 = 15~\text{rad/s}.

  2. Sample 2difficulty 1/5

    A wheel of radius 0.30 m0.30~\text{m} rolls without slipping at 6.0 m/s6.0~\text{m/s}. Its angular speed is

    • A

      2.0 rad/s2.0~\text{rad/s}

    • B

      20 rad/s20~\text{rad/s}

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    • C

      18 rad/s18~\text{rad/s}

    • D

      1.8 rad/s1.8~\text{rad/s}

    Why

    ω=v/R=6.0/0.30=20 rad/s\omega = v/R = 6.0/0.30 = 20~\text{rad/s}.

  3. Sample 3difficulty 2/5

    A solid sphere and a solid disk (same mass and radius) roll without slipping down the same incline from rest. Which arrives first?

    • A

      Depends on incline angle

    • B

      Tie

    • C

      Disk

    • D

      Sphere

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    Why

    a=gsinθ/(1+k)a = g\sin\theta/(1 + k) where k=I/(MR2)k = I/(MR^2). Sphere k=2/5k = 2/5, disk k=1/2k = 1/2. Smaller kk wins → sphere.

  4. Sample 4difficulty 2/5

    v

    A wheel of radius 0.20 m0.20~\text{m} rolls without slipping at v=4 m/sv = 4~\text{m/s}. The angular speed of the wheel is

    • A

      0.05 rad/s0.05~\text{rad/s}

    • B

      5 rad/s5~\text{rad/s}

    • C

      20 rad/s20~\text{rad/s}

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    • D

      0.80 rad/s0.80~\text{rad/s}

    Why

    ω=v/R=4/0.20=20 rad/s\omega = v/R = 4/0.20 = 20~\text{rad/s}.

  5. Sample 5difficulty 3/5

    A solid disk rolls up an incline without slipping. As it rolls up, its angular velocity

    • A

      Reverses sign

    • B

      Decreases

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    • C

      Increases

    • D

      Stays the same

    Why

    KE decreases as PE increases (energy conservation), so both translational and angular speeds decrease.