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Frequency and Period of SHM

AP Physics 1· difficulty 2/5

A pendulum has period TT on Earth (gravity gg). On a planet with g′=g/4g' = g/4, the same pendulum's period is

  • A

    TT

  • B

    4T4T

  • C

    T/2T/2

  • D

    2T2T

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Explanation

T=2πL/gT = 2\pi\sqrt{L/g}. If g→g/4g \to g/4, T→2πL/(g/4)=2⋅2πL/g=2TT \to 2\pi\sqrt{L/(g/4)} = 2 \cdot 2\pi\sqrt{L/g} = 2T.

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