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Frequency and Period of SHM

AP Physics 1· difficulty 2/5

A simple pendulum of length 0.40 m0.40~\text{m} on Earth has period closest to (using π2≈10\pi^2 \approx 10, g≈10 m/s2g \approx 10~\text{m/s}^2):

  • A

    1.3 s1.3~\text{s}

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  • B

    2.0 s2.0~\text{s}

  • C

    4.0 s4.0~\text{s}

  • D

    0.4 s0.4~\text{s}

Explanation

T=2π0.40/10=2π0.04=2π(0.20)≈1.26 sT = 2\pi\sqrt{0.40/10} = 2\pi\sqrt{0.04} = 2\pi(0.20) \approx 1.26~\text{s}.

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