A 0.50\text{kg} block slides at 4\text{m/s} along a frictionless surface and compresses a horizontal spring (k = 50\text{N/m}). Its <strongspeed</strong when the spring is compressed 0.20\text{m} is

3.5\text{m/s} \tfrac{1}{2}m v^2 = \tfrac{1}{2}m v0^2 - \tfrac{1}{2}k x^2. v^2 = 16 - 2(\tfrac{1}{2})(50)(0.04)/0.50 = 16 - 4 = 12. v \approx 3.5\text{m/s}.

school

Acemy

Conservation of Energy

AP Physics 1· difficulty 3/5

0.50~\text{kg}

A
$2.0~\text{m/s}$
B
$3.5~\text{m/s}$
check_circle
C
$4.0~\text{m/s}$
D
$1.0~\text{m/s}$

Explanation

\tfrac{1}{2}m v^2 = \tfrac{1}{2}m v_0^2 - \tfrac{1}{2}k x^2

Want 10 more like this — adaptive to your weak spots?

Practice 10 like thisarrow_forward Predict my AP score

Related questions