Conservation of Energy

AP Physics 1· difficulty 2/5

A pendulum is released from rest with the string horizontal (length LL). Using g10 m/s2g \approx 10~\text{m/s}^2, the bob's speed at the lowest point is

  • A

    gL\sqrt{gL}

  • B

    2gL\sqrt{2gL}

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  • C

    gLgL

  • D

    2gL2\sqrt{gL}

Explanation

Drop = LL. 12v2=gLv=2gL\tfrac{1}{2}v^2 = gL \Rightarrow v = \sqrt{2gL}.

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