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Conservation of Energy

AP Physics 1· difficulty 2/5

A pendulum bob is released from rest at height 0.20 m0.20~\text{m} above its lowest point. Using g≈10 m/s2g \approx 10~\text{m/s}^2 and ignoring air resistance, what is its speed at the bottom?

  • A

    4.0 m/s4.0~\text{m/s}

  • B

    3.0 m/s3.0~\text{m/s}

  • C

    1.0 m/s1.0~\text{m/s}

  • D

    2.0 m/s2.0~\text{m/s}

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Explanation

v=2gh=2(10)(0.20)=4=2.0 m/sv = \sqrt{2gh} = \sqrt{2(10)(0.20)} = \sqrt{4} = 2.0~\text{m/s}.

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