Conservation of Energy

AP Physics 1· difficulty 4/5

A 2.0 kg block slides down a frictionless ramp from height 5.0 m onto a horizontal surface with μk=0.40\mu_k = 0.40. How far does it slide on the rough surface? (g=10g = 10 m/s²)

  • A

    2.5 m

  • B

    20 m

  • C

    12.5 m (mgh=μkmgdmgh = \mu_k mg \cdot d, so d=h/μkd = h/\mu_k)

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  • D

    5.0 m

Explanation

All gravitational PE converts to KE then dissipates as friction work. mgh=μkmgdmgh = \mu_k mg d, d=h/μk=5.0/0.40=12.5d = h/\mu_k = 5.0/0.40 = 12.5 m.

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