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Change in Momentum and Impulse

AP Physics 1· difficulty 3/5

A 1000 kg1000~\text{kg} car at 10 m/s10~\text{m/s} collides head-on with an identical car at rest and they couple. The energy lost in the collision is

  • A

    00

  • B

    100,000 J100{,}000~\text{J}

  • C

    50,000 J50{,}000~\text{J}

  • D

    25,000 J25{,}000~\text{J}

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Explanation

v′=10/2=5 m/sv' = 10/2 = 5~\text{m/s}. Ki=12(1000)(100)=50,000K_i = \tfrac{1}{2}(1000)(100) = 50{,}000. Kf=12(2000)(25)=25,000K_f = \tfrac{1}{2}(2000)(25) = 25{,}000. Lost 25,000 J25{,}000~\text{J}.

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