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Systems and Center of Mass

AP Physics 1· difficulty 2/5

Three masses on the x-axis: 1 kg1~\text{kg} at x=0x = 0, 2 kg2~\text{kg} at x=4 mx = 4~\text{m}, 1 kg1~\text{kg} at x=8 mx = 8~\text{m}. The center of mass is at

  • A

    6 m6~\text{m}

  • B

    2 m2~\text{m}

  • C

    8/3 m8/3~\text{m}

  • D

    4 m4~\text{m}

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Explanation

xcm=(1⋅0+2⋅4+1⋅8)/4=16/4=4 mx_\text{cm} = (1 \cdot 0 + 2 \cdot 4 + 1 \cdot 8)/4 = 16/4 = 4~\text{m}.

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AP Physics 1 · Systems and Center of Mass Practice Question | Acemy