Systems and Center of Mass

AP Physics 1· difficulty 2/5

Masses m1=1 kgm_1 = 1~\text{kg} at x1=0x_1 = 0 and m2=3 kgm_2 = 3~\text{kg} at x2=4 mx_2 = 4~\text{m}. Where is the center of mass?

  • A

    4 m4~\text{m}

  • B

    2 m2~\text{m}

  • C

    1 m1~\text{m}

  • D

    3 m3~\text{m}

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Explanation

xcm=(m1x1+m2x2)/(m1+m2)=(0+12)/4=3 mx_{\text{cm}} = (m_1 x_1 + m_2 x_2)/(m_1 + m_2) = (0 + 12)/4 = 3~\text{m}.

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