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Change in Momentum and Impulse

AP Physics 1· difficulty 3/5

A 0.20 kg0.20~\text{kg} ball hits a wall horizontally at 8.0 m/s8.0~\text{m/s} and rebounds elastically at 8.0 m/s8.0~\text{m/s}. What is the magnitude of the impulse the wall delivers to the ball?

  • A

    3.2 N⋅s3.2~\text{N·s}

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  • B

    8.0 N⋅s8.0~\text{N·s}

  • C

    0.8 N⋅s0.8~\text{N·s}

  • D

    1.6 N⋅s1.6~\text{N·s}

Explanation

Δp=m(vf−vi)=(0.20)(+8.0−(−8.0))=3.2 kg⋅m/s\Delta p = m(v_f - v_i) = (0.20)(+8.0 - (-8.0)) = 3.2~\text{kg·m/s}, directed away from the wall.

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