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Representing Motion

AP Physics 1· difficulty 2/5

An object starts from rest. The aa-vs-tt graph shows constant acceleration of 5 m/s25~\text{m/s}^2 from t=1 st = 1~\text{s} to t=4 st = 4~\text{s}, and zero otherwise. The velocity at t=6 st = 6~\text{s} is

  • A

    5 m/s5~\text{m/s}

  • B

    00

  • C

    15 m/s15~\text{m/s}

    check_circle
  • D

    30 m/s30~\text{m/s}

Explanation

Velocity is the integral of aa: area under the rectangle = 5×3=15 m/s5 \times 3 = 15~\text{m/s}. Beyond that, a=0a = 0, so vv stays at 15 m/s15~\text{m/s}.

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