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Displacement, Velocity, and Acceleration

AP Physics 1· difficulty 2/5

A car needs 30 m30~\text{m} to stop from 20 m/s20~\text{m/s} on dry asphalt. On the same surface, what stopping distance is needed from 30 m/s30~\text{m/s}?

  • A

    45 m45~\text{m}

  • B

    67.5 m67.5~\text{m}

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  • C

    60 m60~\text{m}

  • D

    90 m90~\text{m}

Explanation

d∝v2d \propto v^2. Ratio: d2/d1=(30/20)2=2.25d_2/d_1 = (30/20)^2 = 2.25. So d2=30×2.25=67.5 md_2 = 30 \times 2.25 = 67.5~\text{m}.

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