A rock is dropped from rest from the same height on Earth (gE = 10\text{m/s}^2) and on the Moon (gM = 1.6\text{m/s}^2). The ratio of times to fall tM/tE is closest to

2.5 t \propto \sqrt{1/g}, so tM/tE = \sqrt{gE/gM} = \sqrt{10/1.6} = \sqrt{6.25} = 2.5.

Displacement, Velocity, and Acceleration

AP Physics 1· difficulty 2/5

g_E = 10~\text{m/s}^2

Explanation

t \propto \sqrt{1/g}

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