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Vectors and Motion in Two Dimensions

AP Physics 1· difficulty 3/5

An object is launched from a 25 m25~\text{m} cliff horizontally at 10 m/s10~\text{m/s}. Using g≈10 m/s2g \approx 10~\text{m/s}^2, how far from the base of the cliff does it land?

  • A

    10 m10~\text{m}

  • B

    22 m22~\text{m}

    check_circle
  • C

    50 m50~\text{m}

  • D

    25 m25~\text{m}

Explanation

Time to fall: t=2(25)/10=5≈2.24 st = \sqrt{2(25)/10} = \sqrt{5} \approx 2.24~\text{s}. Range: x=(10)(2.24)≈22 mx = (10)(2.24) \approx 22~\text{m}.

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