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Vectors and Motion in Two Dimensions

AP Physics 1· difficulty 2/5

For the launch above, what is the horizontal range?

  • A

    20 m20~\text{m}

  • B

    40 m40~\text{m}

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  • C

    30 m30~\text{m}

  • D

    80 m80~\text{m}

Explanation

R=v02sin⁡(2θ)/g=(20)2sin⁡90∘/10=400/10=40 mR = v_0^2 \sin(2\theta)/g = (20)^2 \sin 90^\circ /10 = 400/10 = 40~\text{m}.

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