Vectors and Motion in Two Dimensions

AP Physics 1· difficulty 2/5

A ball is launched from level ground at 20 m/s20~\text{m/s} at 4545^\circ above horizontal. Using g10 m/s2g \approx 10~\text{m/s}^2, how long is it in the air?

  • A

    4.0 s4.0~\text{s}

  • B

    1.4 s1.4~\text{s}

  • C

    2.8 s2.8~\text{s}

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  • D

    2.0 s2.0~\text{s}

Explanation

vy0=20sin4514.1 m/sv_{y0} = 20\sin 45^\circ \approx 14.1~\text{m/s}. Time of flight on level ground: t=2vy0/g=2(14.1)/102.8 st = 2 v_{y0}/g = 2(14.1)/10 \approx 2.8~\text{s}.

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