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Pressure

AP Physics 1· difficulty 4/5

h P P0

A U-tube manometer has mercury (ρ=13600\rho = 13600 kg/m3^3). The closed-side fluid level is h=0.30h = 0.30 m higher than open side. What is the gauge pressure of the gas?

  • A

    +4.0×104+4.0\times10^4 Pa

  • B

    −4.0×104-4.0\times10^4 Pa

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  • C

    −4.0×103-4.0\times10^3 Pa

  • D

    +4.0×103+4.0\times10^3 Pa

Explanation

Closed side higher means gas pressure is below atmospheric: Pgauge=−ρgh=−(13600)(9.8)(0.30)≈−4.0×104P_{gauge} = -\rho g h = -(13600)(9.8)(0.30) \approx -4.0\times10^4 Pa.

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