Pressure

AP Physics 1· difficulty 4/5

F1, A F2, 5A

A hydraulic lift has piston areas AA and 5A5A. A force F1=200F_1 = 200 N is applied on the small piston. What is the maximum force F2F_2 available on the large piston?

  • A

    50005000 N

  • B

    10001000 N

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  • C

    200200 N

  • D

    4040 N

Explanation

Pascal: F1/A=F2/(5A)F_1/A = F_2/(5A), so F2=5(200)=1000F_2 = 5(200) = 1000 N.

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