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Frequency and Period of SHM

AP Physics 1· difficulty 4/5

A simple pendulum has period TE=2.0 sT_E = 2.0\text{ s} on Earth (g=9.8 m/s2g = 9.8\text{ m/s}^2). What is its period on the Moon, where gM≈g/6g_M \approx g/6?

  • A

    ≈0.82 s\approx 0.82\text{ s}

  • B

    ≈2.0 s\approx 2.0\text{ s}

  • C

    ≈12 s\approx 12\text{ s}

  • D

    ≈4.9 s\approx 4.9\text{ s}

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Explanation

T∝1/gT \propto 1/\sqrt{g}. So TM=TE6≈2.0(2.449)≈4.9 sT_M = T_E\sqrt{6} \approx 2.0(2.449) \approx 4.9\text{ s}.

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