Frequency and Period of SHM

AP Physics 1· difficulty 2/5

A simple pendulum of length 1.0 m1.0~\text{m} swings through small angles (use g10 m/s2g \approx 10~\text{m/s}^2, take π210\pi^2 \approx 10). Approximately what is its period?

  • A

    1.0 s1.0~\text{s}

  • B

    2.0 s2.0~\text{s}

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  • C

    6.3 s6.3~\text{s}

  • D

    3.1 s3.1~\text{s}

Explanation

T=2πL/g2π1.0/102π(0.316)2.0 sT = 2\pi\sqrt{L/g} \approx 2\pi\sqrt{1.0/10} \approx 2\pi(0.316) \approx 2.0~\text{s} (using π3.16\pi \approx 3.16).

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