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Newton's Second Law in Rotational Form

AP Physics 1· difficulty 4/5

Two masses (3 kg, 2 kg) hang on a frictionless pulley modeled as a disk (I=MR2/2I = MR^2/2, M=1M = 1 kg). The system's acceleration is approximately

  • A

    1.781.78 m/s²

    check_circle
  • B

    9.809.80 m/s²

  • C

    1.961.96 m/s²

  • D

    0.980.98 m/s²

Explanation

a=(m1−m2)g/(m1+m2+M/2)=1⋅9.8/(3+2+0.5)=9.8/5.5≈1.78a = (m_1-m_2)g/(m_1+m_2+M/2) = 1\cdot 9.8/(3+2+0.5) = 9.8/5.5 \approx 1.78 m/s².

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