Conservation of Energy

AP Physics 1· difficulty 2/5

A frictionless cart starts at rest at height h0h_0. Its speed at height h<h0h < h_0 is

  • A

    2gh\sqrt{2 g h}

  • B

    2g(h0h)\sqrt{2 g (h_0 - h)}

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  • C

    2gh0\sqrt{2 g h_0}

  • D

    2g(h0+h)\sqrt{2 g (h_0 + h)}

Explanation

Energy: 12v2=g(h0h)\tfrac{1}{2}v^2 = g(h_0 - h), so v=2g(h0h)v = \sqrt{2g(h_0 - h)}.

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