A 5\text{kg} and a 2\text{kg} mass hang over an ideal pulley. Using g \approx 10\text{m/s}^2, what is the tension in the rope?

29\text{N} a = (m1 - m2)g/(m1 + m2) = (3)(10)/7 \approx 4.3\text{m/s}^2. For lighter mass: T - m2 g = m2 a \Rightarrow T = 2(10 + 4.3) \approx 28.6\text{N}, closest to 29\text{N}.

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Acemy

Newton's Second Law (Translational Dynamics)

AP Physics 1· difficulty 3/5

5~\text{kg}

A
$29~\text{N}$
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B
$14~\text{N}$
C
$50~\text{N}$
D
$20~\text{N}$

Explanation

a = (m_1 - m_2)g/(m_1 + m_2) = (3)(10)/7 \approx 4.3~\text{m/s}^2

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