Spring Forces

AP Physics 1· difficulty 2/5

3 kg

A 3 kg3~\text{kg} mass hangs in equilibrium from a spring with k=150 N/mk = 150~\text{N/m}. Using g10 m/s2g \approx 10~\text{m/s}^2, the stretch from natural length is

  • A

    0.15 m0.15~\text{m}

  • B

    0.05 m0.05~\text{m}

  • C

    0.20 m0.20~\text{m}

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  • D

    0.30 m0.30~\text{m}

Explanation

kx=mgx=30/150=0.20 mk x = m g \Rightarrow x = 30/150 = 0.20~\text{m}.

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