Spring Forces

AP Physics 1· difficulty 3/5

Two identical springs (each kk) connected in <strong>series</strong> behave as a single equivalent spring of constant

  • A

    4k4k

  • B

    2k2k

  • C

    k/2k/2

    check_circle
  • D

    kk

Explanation

Total stretch under force FF: x=F/k+F/k=2F/kx = F/k + F/k = 2 F/k, so keq=F/x=k/2k_\text{eq} = F/x = k/2.

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