Newton's Second Law (Translational Dynamics)

AP Physics 1· difficulty 3/5

A 4 kg4~\text{kg} block on a horizontal table (μk=0.10\mu_k = 0.10) is connected by a string over a pulley to a hanging 3 kg3~\text{kg} mass. Using g10 m/s2g \approx 10~\text{m/s}^2, the system's acceleration is

  • A

    5.0 m/s25.0~\text{m/s}^2

  • B

    2.6 m/s22.6~\text{m/s}^2

  • C

    1.0 m/s21.0~\text{m/s}^2

  • D

    3.7 m/s23.7~\text{m/s}^2

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Explanation

Hanging weight: 30 N30~\text{N}. Table friction: 0.10410=4 N0.10 \cdot 4 \cdot 10 = 4~\text{N}. Net 26 N26~\text{N} on 7 kg7~\text{kg}: a=26/73.71 m/s2a = 26/7 \approx 3.71~\text{m/s}^2.

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