A block on a 30^\circ incline (\muk = 0.10) slides <strongup</strong the slope. Using g \approx 10\text{m/s}^2, what is the magnitude of its deceleration along the incline?

5.9\text{m/s}^2 Going up, both gravity component and friction oppose motion: a = g(\sin\theta + \muk \cos\theta) = 10(0.5 + 0.0866) \approx 5.87\text{m/s}^2.

Newton's Second Law (Translational Dynamics)

AP Physics 1· difficulty 3/5

30^\circ

A
$5.0~\text{m/s}^2$
B
$10~\text{m/s}^2$
C
$4.1~\text{m/s}^2$
D
$5.9~\text{m/s}^2$
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Explanation

a = g(\sin\theta + \mu_k \cos\theta) = 10(0.5 + 0.0866) \approx 5.87~\text{m/s}^2

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