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Circular Motion

AP Physics 1· difficulty 2/5

A car drives over a circular hill of radius 50 m50~\text{m} at the top. What is the maximum speed without leaving the surface? (g≈10 m/s2g \approx 10~\text{m/s}^2.)

  • A

    50 m/s50~\text{m/s}

  • B

    22 m/s22~\text{m/s}

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  • C

    10 m/s10~\text{m/s}

  • D

    70 m/s70~\text{m/s}

Explanation

At the top, mg−N=mv2/rm g - N = m v^2/r. Maximum vv when N=0N = 0: vmax=gr=500≈22 m/sv_\text{max} = \sqrt{g r} = \sqrt{500} \approx 22~\text{m/s}.

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