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Kinetic and Static Friction

AP Physics 1· difficulty 2/5

A block is launched up a frictionless 30∘30^\circ incline at 6.0 m/s6.0~\text{m/s}. Using g≈10 m/s2g \approx 10~\text{m/s}^2, how high (vertical) does it rise?

  • A

    6.0 m6.0~\text{m}

  • B

    3.6 m3.6~\text{m}

  • C

    1.8 m1.8~\text{m}

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  • D

    0.6 m0.6~\text{m}

Explanation

Energy: 12v2=gh⇒h=36/20=1.8 m\tfrac{1}{2}v^2 = g h \Rightarrow h = 36/20 = 1.8~\text{m}. (You don't even need the angle for the vertical-height question.)

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