At the <strongbottom</strong of a vertical loop, the normal force on the rider of mass m moving with speed v in a loop of radius R is

m v^2/R + m g At the bottom, normal force points up and gravity down; net upward must equal centripetal: N - m g = m v^2/R \Rightarrow N = m v^2/R + m g.

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Acemy

Circular Motion

AP Physics 1· difficulty 3/5

m

A
$m v^2/R$
B
$m v^2/R + m g$
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C
$m v^2/R - m g$
D
$m g$

Explanation

N - m g = m v^2/R \Rightarrow N = m v^2/R + m g

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