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Circular Motion

AP Physics 1· difficulty 2/5

A 0.50 kg0.50~\text{kg} ball on a string is whirled in a horizontal circle of radius 0.80 m0.80~\text{m} at constant speed 4.0 m/s4.0~\text{m/s}. What is the tension in the string?

  • A

    10 N10~\text{N}

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  • B

    2.0 N2.0~\text{N}

  • C

    5.0 N5.0~\text{N}

  • D

    16 N16~\text{N}

Explanation

T=mv2/r=(0.50)(4.0)2/0.80=8.0/0.80=10 NT = m v^2/r = (0.50)(4.0)^2/0.80 = 8.0/0.80 = 10~\text{N}.

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