A weight W = 50\text{N} hangs in equilibrium. String 1 makes 60^\circ below the horizontal ceiling and supports the weight. String 2 is horizontal. What is the tension in <strongstring 2</strong?

29\text{N} Vertical: T1 \sin 60^\circ = W \Rightarrow T1 = 50/0.866 \approx 58\text{N}. Horizontal: T2 = T1 \cos 60^\circ \approx 58 \times 0.5 = 29\text{N}.

Newton's First Law (Translational Equilibrium)

AP Physics 1· difficulty 3/5

W = 50~\text{N}

A
$29~\text{N}$
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B
$25~\text{N}$
C
$50~\text{N}$
D
$58~\text{N}$

Explanation

T_1 \sin 60^\circ = W \Rightarrow T_1 = 50/0.866 \approx 58~\text{N}

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