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Forces and Free-Body Diagrams

AP Physics 1· difficulty 2/5

A 2.0 kg2.0~\text{kg} mass hangs in equilibrium from a vertical spring (k=200 N/mk = 200~\text{N/m}). Using g≈10 m/s2g \approx 10~\text{m/s}^2, by how much is the spring stretched from its natural length?

  • A

    0.05 m0.05~\text{m}

  • B

    0.10 m0.10~\text{m}

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  • C

    0.20 m0.20~\text{m}

  • D

    0.01 m0.01~\text{m}

Explanation

kx=mg⇒x=mg/k=(2⋅10)/200=0.10 mk x = m g \Rightarrow x = m g / k = (2 \cdot 10)/200 = 0.10~\text{m}.

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