A block of mass m on a frictionless \theta-incline is held still by a horizontal force F. The normal force on the block from the incline is

m g \cos\theta + F\sin\theta Equilibrium perpendicular to incline: N = m g\cos\theta + F\sin\theta — the applied horizontal force has a component into the incline that adds to the normal force.

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Acemy

Forces and Free-Body Diagrams

AP Physics 1· difficulty 3/5

m

A
$m g/\cos\theta$
B
$m g \cos\theta + F\sin\theta$
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C
$F\sin\theta$
D
$m g \cos\theta$

Explanation

N = m g\cos\theta + F\sin\theta

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